Jon Adams Services Inc. over 20 years in the Asphalt production industry
Formulas
NOTE: Please enter only NUMBERS into fields below-- Do not enter ' or "
 

To calculate a drum plant's rate of production:

  • Multiply the aggregate tons per hour (x) times 100% minus the moisture content (y)
  • Add the oil tons per hour (z)
  • Assume the following x=209, y=4.3%, z=11.76
 
 

To calculate the length of a slat conveyor at a 45 degree angle:

  • Measure height (h), multiply by 1.41416
  • Assume the following: h=65
  • Example: 65x 1.41416=91.9204 feet long slat at 45 degrees
Enter Height:
 
 

To calculate the speed in feet-per-minute of a slat conveyor, the following is needed:

  • Motor RPM-(rpm)
  • Motor sheave size-(ms)
  • Driven sheave size (ds)
  • Gear box ratio-(gbr)
  • Head sprocket size-(hs)
  • Assume the following: RPM=1755, ms=8", ds=14", gbr=25.13, to 1 and hs=9"
  • Calculate the sheave ratio, i.e.: 8" drive, 14" driven
  • Multiply motor speed by the answer = input RPM
  • Input RPM divided by gear box ratio x diameter of head pulley x.2618=slat speed in feet per minute
  • Example: 8 divided by 14 = .571 x 1755 = 1002.86 input rpm div. 25.13 gbr head shaft rpm 39.91 x 9 = 359.19 x .2618 = 94.04 FPM
Motor RPM:(rpm) Gear box ratio:(gbr)
Motor sheave size:(ms) Head sprocket size:(hs)
Driven sheave size:(ds)

ENTER NUMBERS ONLY

example: 8" = 8
example: 1,755 RPM = 1755

 

Baghouse

It requires approximately 165 CFM of air to produce 1 ton of hot mix.

To find the correct baghouse size of a particular drum:

  • Radius x radius x 3.142 (pi) x *1000 = CFM required
  • Example: Assume a 9 foot drum. 4.5 x 4.5 = 20.25 x 3.142 = 63.6255 x 1000 = 63,625.5 CFM
  • This drum would require a 65,000 CFM baghouse

*1000 equals the air velocity through the dryer/mixer. This figure is usually down around 750 to 850 fpm, but using the 1000 fpm give a little bit of over sizing which is a good thing since you don't want the air flow through the baghouse to limit production rates.

ENTER Radius:

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To find the square feet of cloth in a particular baghouse
you need to know the diameter of bag (D), Length of bag (L), and number of bags (N):

  • The formula is: D x 3.142 = A
  • A div 12 = B
  • B x L = SF (sq. ft. per bag)
  • SF x N = total sq. ft. of cloth in baghouse
Diameter of bag (D) Number of bags (N)
Length of bag (L)
 

To find air to cloth ratio (Should be 5.1 to 1 in batch, and 5.5 to 1 drum plants)

  • Determine square footage of an individual bag (X)
  • Multiply that by the number of bags (Y)
  • Divide that answer by baghouse CFM (Z). X times Y = total square feet of cloth (sq/ft). Z divide sq/ft = air to cloth ratio

Most manufacturers figure drum air velocity at between 900 & 1000 FPM

square footage of an individual bag: baghouse CFM:
number of bags:
 

Pumps:

  • HL225 .01898 gallons per revolution
  • K225 .1055 gallons per revolution
  • L225 .23 gallons per revolution
  • 2" Q34 .23 gallons per revolution
  • 3" Q34 .61 gallons per revolution
 

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